Hello Monks , How can I a pass more than one word for one option : for example if my script take the option -w , then I want to be able to do somthing like this : 
perl myScript.pl -w word1 word2

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so word1 and word2 are one argument passed with -w , now I wanted to treat each one seprate. my code looks like this : 
my $usage = "Usage:  $0 -t TARGET -r RELEASE -b BUILDTYPE
  where:
  TARGET    = {all|esel|esci|sci|btsc|sbc|cn|cis}
  RELEASE   = number + optional buildid for the build 
  BUILDTYPE = {clean|incremental|inc} -- note last two ";
         
my $TARGET=undef;
my $RELEASE=undef;
my $BUILDTYPE=undef;
my $TARGET_FOUND="0";
my $BASEDIR="";
my $DRIVENAME;
my $NICE;

while(@ARGV){
   my $argin = shift;
   if ($argin =~ /-t/){$TARGET= shift}
   if ($argin =~ /-r/){$RELEASE=shift}
   if ($argin =~ /-b/){$BUILDTYPE=shift}
}

if (( !defined $TARGET ) or ( !defined $RELEASE ) or ( !defined $BUILD
+TYPE)) {print $usage;exit;}

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so I want to pass more than one RELEASE for the -r option and deal with each one ,, I hope this is clear ,,, thanks for help and hints.

In reply to Passing Options by DS

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