I suspect it will be by way of one of the new pseudopackages - as an educated guess, since all blocks are really closures in Perl 6, I'd say CALLER::. So my $x = $CALLER::x; will probably do that.

Or I may be entirely wrong. :-)

Makeshifts last the longest.

In reply to Re^3: Variable scope in ternary ?: operator not propagating? by Aristotle
in thread Variable scope in ternary ?: operator not propagating? by JayBonci

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