You have a typo and meant ||= instead of =||.

In the case of (A,B) ||= C, (A,B) || ... is the comma operator in scalar context. It evaluates the left argument A, then the right argument B and returns B. Thus you've just written A; B ||= C;.

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In reply to Re^5: Why are "a ||= b" and "a = a || b" different? by diotalevi
in thread Why are "a ||= b" and "a = a || b" different? by saintmike

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