Re: Problems with grep

# works up to here - grep outputs a string, right? But when I get to t +he next line, I get the scalar/count output...
Grep returns scalars, example

D:\>perl -e"die grep /6/, 3 .. 6,6,6"
666 at -e line 1.
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your problem is you're misusing split, example

D:\>perl -e"die split 1, 121314"
234 at -e line 1.

D:\>perl -e"die split 1, 121314, 1"
121314 at -e line 1.

D:\>perl -e"die split 1, 121314, 2"
21314 at -e line 1.

D:\>perl -e"die split 1, 121314, 3"
2314 at -e line 1.

D:\>perl -e"die split 1, 121314, 4"
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you may have intended

 my @matched_cve = map { split(',', $_) } @matched;
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Comment on Re: Problems with grep Select or Download Code

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Re^2: Problems with grep by citromatik (Curate) on Jan 30, 2009 at 14:36 UTC
Grep returns scalars, example `D:\>perl -e"die grep /6/, 3 .. 6,6,6" 666 at -e line 1.` [download] grep returns a list, and in scalar context, the number of elements the expression was true. In your example, die outputs the list returned by grep: `perl -e "die scalar grep /6/, 3 .. 6,6,6" 3 at -e line 1.` [download] What you did is essentially the same as: `perl -e 'die qw/1 2 3/' 123 at -e line 1.` [download] citromatik	[reply] [d/l] [select]
Re^3: Problems with grep by Anonymous Monk on Jan 30, 2009 at 14:58 UTC
`\| \\|/ scalars<-- /\|\ \|` [download] `perldoc -f grep` is better :)	[reply] [d/l] [select]
Re^4: Problems with grep by citromatik (Curate) on Jan 30, 2009 at 15:11 UTC
~~That is not correct, as I said before grep returns a list, and that list is not restricted to be a list of scalars as you are claiming:~~ update: References are scalars, sorry for the confusion `use strict; use warnings; use Data::Dumper; my @t = ( [1,2,3], 0, [4,5,6] ); my @k = grep { ref $_ eq "ARRAY" } @t; print Dumper \@k;` [download] Outputs: `531(255)[1603][/home/pignatelli/tmp]$ perl kkk.pl $VAR1 = [ [ 1, 2, 3 ], [ 4, 5, 6 ] ];` [download] citromatik	[reply] [d/l] [select]
Re^5: Problems with grep by ikegami (Patriarch) on Jan 30, 2009 at 15:31 UTC
Re^2: Problems with grep by spstansbury (Monk) on Jan 30, 2009 at 14:59 UTC
I knew that I was misusing something! Thanks for your help... As a brand new member, I can only say that I am astounded by the support here. The timeliness and helpfulness of the responses is incredible! Thank you all again! Scott...	[reply]
Re^3: Problems with grep by locked_user sundialsvc4 (Abbot) on Jan 30, 2009 at 16:44 UTC
Welcome. “Come, friend, and do likewise.”