Re: hash of hashes of lists!!!

line 176 is

foreach $key (sort keys %$hashOfFiles) 
{
    #LINE 176
    foreach my $file (sort keys %$key) 
    {
           my ($mode2, $user2, $group2, $size2, $mtime2, $filename, $f
+ilepath) = @{$hashOfFiles->{$key}->{$file}};
        print "$file - $filename, $filepath, $mode2 $user2, $group2, $
+size2, $mtime2<br>";
       }
}
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I am using arrays and not lists. Sorry for not making it clear. I am updating my code from a previous version so i am sure that the array works fine.

You said: $foo->{bar}->{baz}
The failure is recognising 'bar' as a scalar rather than a hash and is (i think) nothing to do with 'baz' being a scalar or array.

Comment on Re: hash of hashes of lists!!! Download Code

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Re: Re: hash of hashes of lists!!! by Juerd (Abbot) on Apr 05, 2002 at 15:15 UTC
The failure is recognising 'bar' as a scalar rather than a hash and is (i think) nothing to do with 'baz' being a scalar or array. bar is an unquoted string, baz is an unquoted string. $foo->{bar} is a scalar, holding a hash reference. %{ $foo->{bar} } is the hash to which $foo->{bar} is refering. $foo->{bar}->{baz} is a scalar. U28geW91IGNhbiBhbGwgcm90MTMgY W5kIHBhY2soKS4gQnV0IGRvIHlvdS ByZWNvZ25pc2UgQmFzZTY0IHdoZW4 geW91IHNlZSBpdD8gIC0tIEp1ZXJk	[reply]

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Re: Re: hash of hashes of lists!!!
by Juerd (Abbot) on Apr 05, 2002 at 15:15 UTC

The failure is recognising 'bar' as a scalar rather than a hash and is (i think) nothing to do with 'baz' being a scalar or array.

bar is an unquoted string, baz is an unquoted string.
$foo->{bar} is a scalar, holding a hash reference.
%{ $foo->{bar} } is the hash to which $foo->{bar} is refering.
$foo->{bar}->{baz} is a scalar.

U28geW91IGNhbiBhbGwgcm90MTMgY
W5kIHBhY2soKS4gQnV0IGRvIHlvdS
ByZWNvZ25pc2UgQmFzZTY0IHdoZW4
geW91IHNlZSBpdD8gIC0tIEp1ZXJk

[reply]