~ Printing the variable in each line is only showing the current value..
That is excatly my point. Since, what to print when '1' is seen is not known, I think is better to leave it out.
Your output:
A (yes)
1 (yes) #?
1 (yes) #?
1 (yes) #?
B (no)
1 (no) #?
1 (no) #?
1 (no) #?
A (yes)
1 (yes) #?
1 (yes) #?
1 (yes) #?
B (no)
1 (no) #?
1 (no) #?
1 (no) #?
Output with a little modification:
A (yes)
B (no)
A (yes)
B (no)
OR one can provide for '1' in hash like so:
my %decision = ( A => 'yes', B=> 'no', '1'=>'', );
Then the output shows:
A (yes)
1 ()
1 ()
1 ()
B (no)
1 ()
1 ()
1 ()
A (yes)
1 ()
1 ()
1 ()
B (no)
1 ()
1 ()
1 ()
Just saying.....
If you tell me, I'll forget.
If you show me, I'll remember.
if you involve me, I'll understand.
--- Author
unknown to me
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