Yes, $#rocks = 2; made your array unaware of subsequent elements (though the memory may still be intact, but I don't think the underlying datastructure can be reverted easily); however $#rocks = 99; probably overwrote the memory forever with undefs. I don't know what memory managment magic is invoked here, but I think on a high level that's an accurate way to think about it.

In reply to Re^3: What's going on in array element assignment? by perlfan
in thread What's going on in array element assignment? by zapdos

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