How do I get the variable "$email" to work inside of the below line of code? When I use the literal email it works just fine.. When I use variable I am not getting the expected value

$SENDVAR1 = q(perl -MDigest::SHA=sha256_hex -E 'say sha256_hex(q/$emai
+l/)');
my $email_SHA256 = qx($SENDVAR1);

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In reply to Single Quote string with Variable by BOK_NEPA

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