But as I said
> If this doesn't convince you that try-and-error isn't a good idea, try adding even more 1s and 2s.
for instance ((1)x 51, (2) x 50)
==>
((101!) / (51!)) / (50!) = 1.99804427433e+29
Cheers Rolf
(addicted to the Perl Programming Language :)
see Wikisyntax for the Monastery
In reply to Re^10: Algorithm RFC: fast (pseudo-)random shuffle with no repetition
by LanX
in thread Algorithm RFC: fast (pseudo-)random shuffle with no repetition
by Anonymous Monk
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