I have corrected my piece of code with our help.

After this is completed then I will add more numbers/complexity to make a list of list program. will add German and English in random order then check for keys and values.

then moving to hash tables as per earlier suggestion

I understand why I can not use the push function(due to french word in place of Spanish , if no Spanish word found)

Still, I see a PROBLEM with my unless section. I am coming up with an empty matrix. trying to use only one hash... 

while(<$in1>){
    chomp;
    my ($ita,$fran)=split /\s*=\s*/; #diventa in due colonne
    $hash{$ita}[1]=$fran; #salva i numeri francesi al loro posto [1]
    
    #se i numeri esiste in ambe matrice
    if ($hash{$ita}[0] and $hash{$ita}[1]){
        print $out "$ita =>",join(',',@{$hash{$ita}}),"\n";        
        } else {
            print $out1 "$ita =>", join(',',@{$hash{$ita}}),"\n";
            }   
    }
close $in1;
close $out;
close $in1;

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In reply to Re^6: Need advice on checking two hashes values and keys by Anonymous Monk
in thread Need advice on checking two hashes values and keys by perlynewby

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