Hello Monks, I am beginner in perl. I have fairly simple problem. I have a file structure below. 

cls1,37,Media.vdenc.abcunit,media_vd
cls2,7,Media.Wigig.plsunit,media_vd
cls3,27,Media.vdenc,media_vd
cls4,47,Media.hevc,media_vd
cls5,57,Media.ENC,media_vd

[download]

I am spliting each line on "," and storing 3rd element in an array (for ex: Media.vdenc.abcunit). I want to print a line in which third field in the element is empty (for ex: Media.vdenc). My idea is to split the each string in an array (cluster) and if third field is empty print that line. Can anyone help me with this? So far I tried: 

#!usr/bin/perl

my $file = $ARGV[0] or die "Please provide csv file \n";

open(my $data , '<', $file ) or die "Cannot open csv file $!\n";

while (my $line = <$data>){
    chomp $line;
my @col = split ",",  $line;
push (my @cluster, $col[2]);

  foreach my $field (@cluster){
      my @cls = split ".", $field;
      print @cls;
  }
}

[download]
Output should be :
cls3,27,Media.vdenc,media_vd
cls4,47,Media.hevc,media_vd
cls5,57,Media.ENC,media_vd

[download]

In reply to Perl split on regex match by Eshan_k

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