Could anyone explain this to me?

Here's the code:

#!/usr/bin/perl -Tw
use strict;

print $#ARGV;
die "where are those args again?\n" unless ($#ARGV > 0);
exit;

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Here's the output without an @ARGV:

where are those args again?<br>
-1

[download]

Here's the question:
Why is the print after the die?

In reply to Does die() change the order of execution? by lo_tech

Title:
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