Works fine for me, without the typo. Was that a cut-n-paste error, or is that your actual code (with the c$ instead of $c in your conditional)? 
my $c = -5;
print "C is now $c\n";

$c = 0 if ($c < 0);
print "C is now $c\n";

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In reply to Re: Conditionally Changing a Variable by joealba
in thread Conditionally Changing a Variable by Anonymous Monk

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