Monks,

I have the following code (*note: IP's have been changed): 
splice(@ips, 15); 
for $i ( 0 .. $#ips ) { 
    print "\t $i is  @{$ips[$i]},\n";
}

Output:
         number 0 is  192.168.36.118 12431 46.08%,
         number 1 is  192.168.80.103 4203 1.56%,
         number 2 is  192.119.15.61 3627 1.34%,
         number 3 is  192.19.125.2 1738 0.64%,
         number 4 is  192.217.1.21 1134 0.42%,
         number 5 is  192.17.214.10 852 0.32%,
         number 6 is  192.2.252.1.768 0.28%,
         number 7 is  192.134.77.97 498 0.18%,
         number 8 is  192.8.29.90 489 0.18%,
         number 9 is  192.11.7.17 409 0.15%,
         number 10 is  192.10.191.29 394 0.15%,
         number 11 is  192.247.91.18 25 0.09%,
         number 12 is  192.229.14.7 231 0.09%,
         number 13 is  192.131.192.206 227 0.08%,
         number 14 is  192.161.31.247 172 0.06%,

[download]

I want to add the first (ip address) and second (number of attempts) columns to their own array. I was able to add the first column with this code: 
my @newips = (); 
my ($x, $y);
$y = 0;  
for ($x = 0; $x < 15; $x++) { 
   push @newips, $ips[$x][$y]
}

[download]
then I tried to add the second column with this code: 
my @num = ();
$x = 0;  
for ($y = 0; $y < 15; $y++) {
   push @num, $ips[$x][$y]
}

[download]
Which only prints:   192.168.36.118 12431  46.08%

What is the best way to do this? I read perllol which got me this far, but now I'm stuck.

Thanks,
Dru

In reply to Array of Arrays Question by dru145

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