Just to complete the record, this does what you want using split:
print join(':', split /(?=(?:..)+$)/,'00a0c801adc6'),"\n<BR>";

[download]
It avoids passing the separator by using non-capturing parens and a "zero-width" match. (And relies on there being an even number of characters.)

  p

In reply to Re: More Help with Regex by petral
in thread More Help with Regex by lucky1

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