Your method of calculating variance can result in loss of significant digits. For example, the following data produces a variance of 0 for X on my machine (causing div-by-zero errors later). The variance should be the same for both X and Y (as the data differs only by a constant). 

999999997	9999997
999999998	9999998
999999999	9999999

Better results may be achieved by "centering" your variance calculation about the mean. 

    my $VX = 0;
    $VX += ($_ - $MX)**2 for @x;
    $VX /= $Xn;

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You are also making far more passes over the data than necessary.

In reply to Re: Statistical data analysis by Anonymous Monk
in thread Statistical data analysis by moxliukas

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