No, it cannot. If you { my $var; some_sub(); }, then some_sub() cannot see $var. On the other hand, if you { local $var; some_sub(); }, then some_sub() can. (And that's why you shouldn't local unless you have a clear reason for it and not before you have signed a contract that you clearly understand that perl is not liable if you botch up at that point, and that you accept the consequences.)

Makeshifts last the longest.

In reply to Re^3: Can't localize lexical variable $var at... by Aristotle
in thread Can't localize lexical variable $var at... by Courage

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