Pipped to the post on the anon array solution, if you really want to retain the semantics of the hash: 

#! perl -w
use strict;

sub roll {
    (  {2=>1, 3=>2, 4=>3, 5=>4, 6=>5, 7=>6, 8=>5, 9=>4, 10=>3, 11=>2, 
+12=>1}->{ shift() || 0 } ) / 36
        or warn "Invalid roll\n" and 0;
}

print roll( $_),$/ for (2..12);

__END__
C:\test>190287
0.0277777777777778
0.0555555555555556
0.0833333333333333
0.111111111111111
0.138888888888889
0.166666666666667
0.138888888888889
0.111111111111111
0.0833333333333333
0.0555555555555556
0.0277777777777778

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What's this about a "crooked mitre"? I'm good at woodwork!

In reply to Re: Converting pascal code to perl by BrowserUk
in thread Converting pascal code to perl by Popcorn Dave

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