This is a simple one-liner:     perl -ne 'print $prev, $_ if /foobar/; $prev = $_' file

However, if there are several consecutive matches it will print duplicated data.

This one doesn't produce duplicates:

perl -ne 'BEGIN{$re=qr/foo/}if(/$re/){print$p if$p!~/$re/;print$_} +;$p=$_' file

If you have a grep that supports it you can also do this:

    grep -B 1 foobar file

And finally, this is a more generalised method of printing a matched line and the n-1 previous lines, with and without duplicates:

perl -ne '$i=$.% 2; $a[$i]=$_; print @a[$i+1..$#a,0..$i] if /foo/' + file perl -ne '$i=$.% 2; $a[$i]=$_; print @a[$i+1..$#a,0..$i] and @a=() + if /foo/' file

--
John.


In reply to Re: grabbing previous line in a log by jmcnamara
in thread grabbing previous line in a log by adonai

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