I have code like this: 
use strict;
...
...
foo;
...
...
sub foo
 { ... }

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and it complains that foo is a bareword, and makes me write the call as foo() instead. Now, doesn't Perl know all the defined functions on an earlier pass? Under what circumstances will it not know the name is a function?

—John

In reply to Forward-referenceing subs by John M. Dlugosz

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