I see, thanks.

In perlop I should've read 

  @a = @b || @c;              # this is wrong
  @a = scalar(@b) || @c;      # really meant this

[download]
instead of misinterpreting
Scalar or list context propagates down to the right operand if it is evaluated.

In reply to Re: Re: Regexp context with || by bsb
in thread Regexp context with || by bsb

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