i slightly modified the c++ version to run it in c, declaring variables and changing cout to printf. it ran compiled (with TURBOC :) ) in 3 secs. i still can't believe there would be such a vast difference between perl and c++...so i fiddled a bit, doing extra printf, and found that for the c/c++ version the value of shift didn't seem to change, ie printf("%d",shift); prints 0's. this wasn't the case in the perl version. maybe i'm doing something wrong, but couldn't figure out why. maybe some other monk (with a C++ compiler -- i'm missing header files in my cygwin gcc) can check this. if my results were correct, then no wonder the c/c++ version ran so fast (turning the shift<<=1; into a no-op)

In reply to Re: Believably slow.. by aquarium
in thread Unbelievably slow.. by kiat

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