use if $type eq 'x', Some::Module;

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Of course, that requires the value of $type to be known at compile time. Otherwise, do something like: 

if ($type eq 'x') {
    require Some::Module;
    Some::Module -> import if Some::Module -> can ("import");
}

[download]

Abigail

In reply to Re: use module if condition is met by Abigail-II
in thread use module if condition is met by Grygonos

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