Geez. This isn't supposed to be obfuscation, but it ended up that way, in the sense that the algorithm is a bit difficult to extract. The swapping is the easy part... those two parallel arrays are not.
# reorder an array using only swap(ARRAY, X, Y), # given a new set of indices my @array = qw( put these in a different order ); my @order = qw( 1 3 5 4 2 0 ); reorder_swap(\@array, \@order); # expected outcome: # qw( these a order different in put ) sub reorder_swap { my ($a, $o) = @_; my @P = my @R = 0 .. $#$o; for (0 .. $#$o) { next if $P[$$o[$_]] == $_; swap($a, $P[$$o[$_]], $_); (@P[$R[$_],$$o[$_]], @R[$P[$$o[$_]],$_]) = (@P[$$o[$_],$R[$_]], @R[$_,$P[$$o[$_]]]); } } sub swap { my ($a, $x, $y) = @_; @$a[$x,$y] = @$a[$y,$x]; }
For simplicity's sake, here's the for loop with a temporary variable instead:
for (0 .. $#$o) { my $idx = $$o[$_]; next if $P[$idx] == $_; swap($a, $P[$idx], $_); (@P[$R[$_],$idx], @R[$P[$idx],$_]) = (@P[$idx,$R[$_]], @R[$_,$P[$idx]]); }
_____________________________________________________
Jeff japhy Pinyan, P.L., P.M., P.O.D, X.S.: Perl, regex, and perl hacker
How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart

In reply to (CLPM) reorder via swap by japhy

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