What I meant was that the subroutine, if written as a named subroutine, isn't a closure. By making it lexical and anonymous you make it one though, ...

That makes no sense to me, but I have a fuzzy definition of Perl's closures, so that may not be surprising.

The confusing part is this. 

{
    my $foo = 1;
    sub get_and_inc_foo { $foo++ }
}

[download]

I was always told that get_and_inc_foo() is a closure over $foo. But, it's neither anonymous nor lexical, so how does that work?

If my example is a closure, then aren't all subroutines closures over the file-scoped lexicals in the file they're defined in?

(Now that I think of it, isn't this the reason why you cannot have globals when using ModRegistry?)

------
We are the carpenters and bricklayers of the Information Age.

Then there are Damian modules.... *sigh* ... that's not about being less-lazy -- that's about being on some really good drugs -- you know, there is no spoon. - flyingmoose

I shouldn't have to say this, but any code, unless otherwise stated, is untested

In reply to Re^5: Is it possible to create a sub exclusive to a sub? (nasty memory leak) by dragonchild
in thread Is it possible to create a sub exclusive to a sub? by punkish

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