This is straightforward to predict when you separate what's happening
on the right side from what's happening on the left.
The list of
(1 => 2, 3 => $x{1} )
Is identical to
(1, 2, 3, undef)
as long as
%x didn't have a previous value.
In fact, it's the prior value of $x{1} that you see, as evidenced
by:
%x{1} = "old x sub 1";
%x =
( 1 => 2,
3 => $x{1}
);
The question for me is, why did you find this surprising or baffling? It's extremely consistent with what Perl does at all times: evaluate the right side of the assignment before altering any structure on the left. It's what permits
@a = (2, @a)
or
@a = reverse sort @a;
to work.
-- Randal L. Schwartz, Perl hacker
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