A subroutine gets it's arguments as an array (@_), so if you do
my @array = (1,2,3,4,5);
some_sub(@array);
Within some_sub,
@_ will equal the contents of
@array.
However, you probably want to pass the array into the subroutine by reference (see
perlref for more):
my @array = (1,2,3,4,5);
some_sub( \@array );
In that case, the first element of
@_, the argument list to some_sub, will be a reference to
@array.
If the information in this post is inaccurate, or just plain wrong, don't just downvote - please post explaining what's wrong.
That way everyone learns.
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