I think what inman is talking about, is creating a line in the cartesian coordinate system, by using 2 adjacent data points. If the "slope" of the line is positive, then shift data points by one, so the "previously second" x value, is now the first, and compute the next slope. Where the slope turns from a positive to negative value, is a "local" peak.

The slope of a line is y = Mx + b, where M is the slope. M is usually (y2 -y1)/(x2 - x1).

I think Pustular Postulant's method is probably faster.

I'm not really a human, but I play one on earth. flash japh

In reply to Re: Any idea for predicting the peak points in the graph by perl by zentara
in thread Any idea for predicting the peak points in the graph by perl by Anonymous Monk

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