Hi Monks

I have a variable which contains perl coding. 

$a='
$text=~s#Find \#Text#Replace Text#;
$text=~s/Find \/Text/Replace Text/;
$text=~s{Find \}Text}{Replace Text};
';

[download]
I need to get find patter and replace patter into variabls from $text variable. 
if ($a=~m#$text=~s(.)\s*(?<!\1)#)
{
    # need value $findtext='Find \#Text';
    # need value $repltext='Replace Text';    
}

[download]

when I ran this, It will showing an error message. 

Variable length lookbehind not implemented in regex; marked by <-- HER
+E in
        m/=~\s*s(.)(?<!\1) <-- HERE / at script.pl line 8 (#1)
    (F) Lookbehind is allowed only for subexpressions whose length is 
+fixed and
    known at compile time. The <-- HERE shows in the regular expressio
+n about
    where the problem was discovered. See perlre.

Uncaught exception from user code:
        Variable length lookbehind not implemented in regex; marked by
+ <-- HERE
in m/=~\s*s(.)(?<!\1) <-- HERE / at script.pl line 8.

[download]

Please guide me how can i do this.

Thanks
Kanishk

In reply to Regexp help!! by kanish

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