If i understood your question correctly, this will work.

'.' matches newline character when you use the 's' option modifier in your regex. Also take a look at perlre.

#! /usr/bin/perl

$str = "aaaaa\nbbbbb\nccccc\naaaaa\nddddd\neeeee\n" ;

@a = $str =~ /aaaaa(?:(?!aaaaa).)*/gs ;

print "$a[0]\n$a[1]" ;

[download]

updated: removed extra grouping.

Thanks in advance

Prasad

In reply to Re: multi-line regexp by prasadbabu
in thread multi-line regexp by jeanluca

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