Well, I did a search, and Nested Ternary Operators and Formatting chained and nested ternary ops (was Re^4: lvalue subs return undef....) didn't really help. Can anyone see why it's not giving 33 or 18 for $result? 
#!/usr/bin/perl -w

use strict;

my $major_length = 8552;
my $val = 4;

# this gives $result as 33, as expected ....
my $result = ($major_length == 4800) ? 18 
        : ($major_length ==  8552) ? 33 : 0;

# this gives $result as 1, not 33.  Makes sense, 
# since $val == 4 evaluates to 1.  But, I want $result to 
# be assigned 33, based on the fact that $val == 4. 
$result = ($major_length == 4800) ? 18 
        : ($major_length ==  8552) 
            ? ($val == 4) : 33;

# this is what I had originally; it gives $result as 1,
#  not 33.
$result = ($major_length == 4800) ? 18 
        : ($major_length ==  8552) 
            ? ($val == 4) : 33
            ? ($val == 1) : 18;

# Putting in parens doesn't help either
#    this gives $result as 1 - but 
# I want it to equal 18 or 33... 
$result = ($major_length == 4800) ? 18 
        : ( ($major_length ==  8552) 
            ? ($val == 4) : ( 33
                          ? ($val == 1) : 18 ) );

print "$result\n";

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-- Burvil

In reply to nested tabular ternary by bowei_99

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