I see. Actually to prevent confusion ... even this would autovivify:

@a  = ( $hash{foo}{bar} x!! 0);

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I guess we'd need to "fix" the x operator to not evaluate the lefthand operator if the righthand one is <=0.

Jenda
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In reply to Re^4: Secret Perl Operators: the boolean list squash operator, x!! by Jenda
in thread Secret Perl Operators: the boolean list squash operator, x!! by Aristotle

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