Hi Monks,
I have one file which contains the information of all the
users who r login to the machine in between 10 minutes,the
file contains fallowing format
time maxusrat_a_time loggeduser usernames
1.00 50 10 x,y,z,w,u,e,g,j,k,a
1.10 50 13 x,y,b,a,g,j,k,r,,n,m,s,
1.20 50 05 c,t,g,q,f
1.50 50 08 a,t,y,w,z,x,s,b
2.00 50 14 x,y,u,b,g,f,s,a,i,o,p,c
from the above file i grouped the usernames in to 3 groups
so,that i want to calculate for a perticilar intervel how meny of group1 ,group2 and group3 are loggedin to the server.

i need result like below 1.00 5(group1)user,5(group2)users are logged in


fallowing is the code i am trying to solve the solution
 @GRP1=(ravindkr,anandku,mparamas,anbarasr,subashin,prakasku,bsendray,
+pregunat,andccadm,nkhuntia,vdeshpan,dbalasub,rbalakri);
@GRP2=(awsdel,lpalanic,masubram,bpakanat,mshifan,asrajama,vidhyan,apat
+nayi,samallik,ikrishna,adityam,susajja,vramana,raghuran);
@GRP3=(mahendrd,ranantan,knittala,sathyam,bmallapr,skummara,prasantn,s
+rivatss,ramack,dmurugap,pparichi,esettu,babuk,hpandura,brengana);
@GRP4=(thendraa,samarenb,slekkala,apatnayi,psundar,isivapra,pjayaram,s
+unandap,speriasa,raallaga,gelango,dchockal,ldash);
open(FH,"_today_data.txt") or die "can't open the file$!\n";
while($line=<FH>)
{
   chomp($line);
    @usr=substr($line,8,2);
    @time=substr($line,0,4); 
     @username=substr($line,16);         
      foreach $a (@username)
        {   
               @username1 = split(',', $a);
                print "@time\t @usr\t @username1\n";  
         }
 }

[download]
keep pouring your ideas.......

In reply to How to match the each line of of users for a perticular time with predeclared group. by perladdict

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