monks, 

#!/usr/bin/perl

use strict;
my $val = 10 ;
my $re = ++$val - $val-- + --$val;
print $re;

output :-
8

[download]
How the result becomes as 8. If I execute this manually based on the operator precedence I suspect it should be 9. but I am wondering about the end result, which is 8. I hope, monks will have a better explanation.

In reply to Doubt in the result which I got from (In|De)crement operators by jesuashok

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