This should get you close to what you want.. 
>perl -e "my $x = qq['foo',123,'bar\\'cuz', 'comma,comma',,'void'];
   map { print qq[<$_;\n]; } $x=~m/((?:'[^']*'|[^'\s,]+|))(?:[$|,\s]|$
+)/g;"

<'foo';
<123;
<'cuz';
<;
<'comma,comma';
<;
<'void';
<;

[download]
There is an extra empty item returned. No easy way to avoid that, that I can think of.
'bar\'cuz' is an invalid text string, in this context, so only 'cuz' is returned.

Note the use of non-capturing parens "(?:" - quite useful in this context, so each iteration returns only a single capture, because the first paren IS a capturing paren.

     "As you get older three things happen. The first is your memory goes, and I can't remember the other two... " - Sir Norman Wisdom

In reply to Re: m//g in list and scalar context differences? by NetWallah
in thread m//g in list and scalar context differences? by oha

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