Using your inspiring one-liner, I morphed my script with yours and came up with this:

/bin/perl -MTime::Local -ne '{$t[1]-- && push(@epochs,timelocal(@t[5,4,3,2,1,6])) if (@t=split)} END { print $epochs[1] - $epochs[0]; }'

The END block is most likely what will change because the value of the diff will be used to determine exit status.

Thanks a lot for the fresh perspective, it was very helpful.

"The three principal virtues of a programmer are Laziness, Impatience, and Hubris. See the Camel Book for why." -- `man perl`

In reply to Re^2: Diff'ing dates by LighthouseJ
in thread Diff'ing dates (solved) by LighthouseJ

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