Thank you all for the replies.
you could stick a loop around the whole thing and call next in the subroutine instead of return
I tried exactly that but it didn't work, complaining that it couldn't find the label.
LABEL: { sub outer { inner(); } sub inner { next LABEL; } }
In reply to Re: exit calling subroutine
by Sixtease
in thread exit calling subroutine
by Sixtease
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