While answering another SoPW question, I wrote a script to convert the spreadsheet column name IV to an integer: 
sub v {
  ord($_[0]) - ord('A');
}

print v('I')*26 + v('V'), "\n";

[download]
This yielded the output: 
shell$ perl ./iv65536
229
shell$

[download]
It then occurred to me that in the column name AB, the A has weight 1 (not weight 0), and so I was off by 26. I therefore modified the formula to: 
print (v('I')+1)*26 + v('V'), "\n";

[download]
and running it produced: 
shell$ perl ./iv65536
9shell$

[download]
Why did it print 9, and where did the newline go?

In reply to Converting "IV" from base 26 by pc88mxer

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