The statement &foo; calls foo using a mirror image of @_ /.../ neither call /.../ modifies @_ as passed to frobnicate

By "mirror image" you mean the same, right? Just to be clear, the call &foo; may actually modify frobnicate's @_.

See Re^2: Using & in function calls (&foo != foo(@_)) for an example.

lodin

In reply to Re^2: $obj->method v.s. $obj->method() by lodin
in thread $obj->method v.s. $obj->method() by perl5ever

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