sub lambda {$_[1]}

our $x = 2;
my $f = lambda $x => sub {$x ** 2};
say $f->();
{
    local $x = 3;
    say $f->();
}
say $f->();
__END__
4
9
4

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Of course, in Perl, one doesn't really need "lambda". Hence a lambda which just returns the sub.

In reply to Re: Local for lexicals by JavaFan
in thread Local for lexicals by JadeNB

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