What are you trying to achieve that this doesn't? 
my( $x, $y, $z ) = ( 1,2,3 );
my $lamb = do{
    my( $x, $y, $z ) = ( $x, $y, $z );
    lambda ( $x, $y, $z ) => sub { $x + $y }
}

[download]
Unfortunately, I don't know quite what this does, so I can't answer! My question (at least, the part of my question that seems to have attracted the most attention) is how to write lambda in such a way that lambda( $x, $y, $z ) => sub { $x + $y } is the same as sub { $_[0] + $_[1] }. As far as I can tell, the code that you've written would be the same as 
my ( $x, $y, $z ) = ( 1, 2, 3 );
lambda ( 1, 2, 3 ) => sub { 1 + 2 }

[download]

In reply to Re^6: Local for lexicals by JadeNB
in thread Local for lexicals by JadeNB

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