Hi monks. I know a little English :( Below is my code. I want to get $path from $target. How I do it in one regexp? Thanks :) 
#!/bin/env perl

use strict;
use warnings;

my $target = "/index.php?prefix=/user/";
my $path = $target;

# How to optimize?
$path =~ s{\?.*$}{};
$path =~ s{[^/]+$}{};

print "$path\n";

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In reply to How to replace in one regexp by appleii

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