It's hard to see why you would want to avoid a hash or database since this seems to be exactly what you need.

That being said, here is a version using arrays of arrays. It's quite inefficient as it cycles through the @arr array for every line of @arr2, but it doesn't use a hash or database.

#!/usr/bin/perl
use strict;
use warnings;

my @arr = (
    [ "1", "Smith",  "Ric" ],
    [ "1", "Smith",  "Rich" ],
    [ "1", "abc",    "A" ],
    [ "1", "cdeQ",   "C Sr" ],
    [ "1", "ghi",    "G" ],
    [ "2", "cdeQ",   "C Sr" ],
    [ "3", "ghi",    "G" ],
    [ "3", "abc",    "A" ],
    [ "3", "Smith",  "Ric" ],
    [ "4", "cde",    "C" ],
    [ "5", "cde",    "C" ],
    [ "5", "xyz123", "X" ],
    [ "5", "cdeQ",   "C II" ],
    [ "5", "Smith",  "Rich" ]
);
# callno lname fi (repeat 3 data points for each FF at each callno)

my @arr2 = (
    [ "1", "S",   "01/05", "04" ],
    [ "2", "EMS", "01/05", "07" ],
    [ "3", "VF",  "01/05", "11" ],
    [ "4", "S",   "01/05", "13" ],
    [ "5", "B",   "01/05", "17" ]
);
# callno  type date hr (repeat 4 data points for each incident)

my $seen;

for my $arr2 (@arr2) {
    if ( $arr2->[3] ) {    # ie, if there's a complete call record
        print "@$arr2\n";
        $seen = $arr2->[0];
        print "\tDEBUG: My \$seen: $seen\n\n";
    }
    for my $arr (@arr) {
        if ( ( $arr->[0] ) && ( $seen == $arr->[0] ) ) {
            print "@$arr\n";
        }
    }
    print "\n\t\tFF Array exhausted for Callno $seen\n";
    next;
}
print "\n\t\t No more calls\n";

[download]

In reply to Re: Iterating two co-dependant arrays by thundergnat
in thread Iterating two co-dependant arrays by ww

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