$ perl -MO=Deparse -e "while(<>){print if($.==2||$&&&!$s++);$.=0 if(/^
+-+$/)}"
while (defined($_ = <ARGV>)) {
    print $_ if $. == 2 or $& and not $s++;
    $. = 0 if /^-+$/;
}
-e syntax OK

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It prints the 2rd line read, and 2nd line after every line of ----. Also, it prints the first line after the first line of ----.

In reply to Re: can you explain this perl oneliner by Anonymous Monk
in thread can you explain this perl oneliner by unixguy

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