I am sorry I have no idea what that does. Please explain. My guess is @x[0]=z, @y[0]=y and @z[0]=z.

When I had the below statement, I was trying to create and initialize values of all variables.

my (%Aseen, %Bseen, %count, @isec, @diff, @union, @aonly) = ();

Please let me know what I'm doing wrong.

Thanks for your help.

In reply to Re^6: Referencing in Function not working correctly. by mr_p
in thread Referencing in Function not working correctly. by mr_p

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