I was trying to convert some code from perl -> perl6 when had to use capture brackets in a substitution (s///)

so in rakudo specifically, this works:
rakudo/perl6 -e 'my $v = "test"; $v ~~ /(\w)/; say $0' # says t

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but this doesn't:
rakudo/perl6 -e 'my $v = "test"; $v ~~ s/(\w)/X/; say $0' # says Any()

[download]


is there a different syntax for subst ? or rakudo haven't implemented this yet ?

In reply to perl6: subst with capture brackets by Fox

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