Why do you need the variable $error? Can't you simply say: 

mkdir $path;
die "Cannot create directory $path : $!\n" unless -d $path;

[download]

? From what I see from the documentation, the -d operator doesn't change $!, does it?
-- 
Ronald Fischer <ynnor@mm.st>

In reply to Re^2: Directory creation in Perl using mkdir by rovf
in thread Directory creation in Perl using mkdir by sselva

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