By your logic, the following never deallocates the referenced array: ...
This isn't even remotely what I said. I said the scalar (i.e. the SV, what you call TARG) is the same, and a copy of it is created when a reference to it is pushed onto the array — nothing more. That's in essence the same you pointed out in your reply.
In reply to Re^3: lexicals are all the same scalar and never go out of scope?
by Eliya
in thread lexicals are all the same scalar and never go out of scope?
by patcat88
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |