package Foo;

sub new { return bless {}, shift }

package main;

my $x = new Foo;
my $y = new Foo;

print "number: ", int $x, " -- ", int $y, "\n";
print "string: $x -- $y\n";

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The following is wrong. Sorry. You've got to love those Perl quirks :)

Using == will always be true when both variables point to something, even though it's not the same object. It'll probably be treated the same as "Whatever" == "Something else".

Use eq, since that will stringify your objects into the form of PackageName=HASH(0xdeadbeef). If they point to the same object, they'll have the same memory address. (the 0xdeadbeef part). If that's the case, the two string will be equal.


[ ar0n ]

In reply to (ar0n) Re: eq or == with references by ar0n
in thread eq or == with references by Anonymous Monk

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