Hi all,

I generally use "my $system = XMLin('/hello/uday_sagar/system.xml');". But I want to give as XMLin('$ARGV[0]/system.xml') and pass /hello/uday_sagar as an agrument from the commandline. How can I achieve this? Please also tell me the way to pass the file handle to the XMLin() method. Thanks in Advance, Uday Sagar.

In reply to Giving the input file to XMLin() from the command line as an argument by uday_sagar

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